function* expression

Try it

const foo = function* () {
  yield "a";
  yield "b";
  yield "c";
};

let str = "";
for (const val of foo()) {
  str += val;
}

console.log(str);
// Expected output: "abc"

Syntax

function* (param0) {
  statements
}
function* (param0, param1) {
  statements
}
function* (param0, param1, /* …, */ paramN) {
  statements
}

function* name(param0) {
  statements
}
function* name(param0, param1) {
  statements
}
function* name(param0, param1, /* …, */ paramN) {
  statements
}

Parameters

name Optional

The function name. Can be omitted, in which case the function is anonymous. The name is only local to the function body.

paramN Optional

The name of a formal parameter for the function. For the parameters' syntax, see the Functions reference.

statements Optional

The statements which comprise the body of the function.

Description

A function* expression is very similar to, and has almost the same syntax as, a function* declaration. The main difference between a function* expression and a function* declaration is the function name, which can be omitted in function* expressions to create anonymous functions. A function* expression can be used as an IIFE (Immediately Invoked Function Expression) which runs as soon as it is defined, allowing you to create an ad-hoc iterable iterator object. See also the chapter about functions for more information.

Examples

Using function* expression

The following example defines an unnamed generator function and assigns it to x. The function yields the square of its argument:

const x = function* (y) {
  yield y * y;
};

Specifications

Browser compatibility

See also

• Functions guide
• Functions
• function*
• GeneratorFunction
• Iteration protocols
• yield
• yield*